Theoretical Tuning Question

Discussion and support for MoTeC's previous generation ECUs.

Re: Theoretical Tuning Question

Postby figgie on Tue Aug 19, 2008 3:43 am

Ian

I think I understand your question so here is by stab at it :)

Is the two options the only options?

more boost less timing or Less boost and more timing?

The answer will be it depends. Given a fuel with infinite octane, you could theoretically crank the boost until the turbo turns itself into a smoldering pile of goo. The same can not be said with timing as even with infinte octane. You can start the combustion process to early . Of course we are making a big assumption that the turbo is efficent at all ranges to make a conclusion of that nature (which of course does not exist). Of course the example I posted is a physics world problem. Real world no such fuel exist so it comes down to trying both until you reach MBT timing on that boost and then see if power is gained by going more boost with less timing.
figgie
 
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Re: Theoretical Tuning Question

Postby CRD on Tue Aug 19, 2008 10:00 pm

Hi guys.
Just thought i might be able to shed some light on a generally straight forward question.
Ok,irrespective of what comp ratio ,engine combo etc you might have ,there are 3 main things that
an experienced engine tuner will always look at to determine the best possible/safest way of working out
how much boost versus how much ignition timing versus what air/fuel ratio to run.
Exhaust gas temps and its stability ,air intake temps and its stability and exhaust back pressure/intake back
pressure build up.
Knowing what each engine needs to achieve the best result is a whole other subject though.
:mrgreen:
But then we are only talking theoretical tuning

hope this helps

Jim Souvas
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Re: Theoretical Tuning Question

Postby figgie on Wed Aug 20, 2008 12:49 am

CRD wrote: exhaust back pressure/intake back
pressure build up.


Hi Jim

here is a question for some thought. In electical circuits, does "back resistance" exist (not to be confused with back inductance or back current)? ;)

"back" pressure is a double negative. In fluid mechanics, Pressure = Resistance to flow. Back pressure = Resistance to the resistance to flow??? :?: ;)
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