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Efficiency Point of a MAF-based system
Posted:
Mon Nov 14, 2011 2:38 am
by Vassili Wang
Hello.
My car has a 4-stroke engine with four cylinders. And I want to use a MAF sensor.
In "help", "Efficiency Point = MAF / inductions per rev / (RPM/60) * 100"
I'd like to know what does " inductions per rev " mean ? For my engine, it should be 0.5 or 2 ?
Thanks a lot.
Re: Efficiency Point of a MAF-based system
Posted:
Mon Nov 14, 2011 5:15 pm
by Holmz
Vassili Wang wrote:Hello.
My car has a 4-stroke engine with four cylinders. And I want to use a MAF sensor.
In "help", "Efficiency Point = MAF / inductions per rev / (RPM/60) * 100"
I'd like to know what does " inductions per rev " mean ? For my engine, it should be 0.5 or 2 ?
Thanks a lot.
2-stroke = 1.0
4-stroke = 0.5
(I suppose, by induction, a 1/2-stroke would be 2 or 4)
Re: Efficiency Point of a MAF-based system
Posted:
Tue Nov 15, 2011 8:03 am
by Scott@FP
It works out to grams air per induction * 100, regardless of cylinder count or size or 2 or 4 stroke. Determined by Gen setup/main setup/# of cylinders, 2 stroke or 4 stroke. If you have a properly calibrated MAF sensor and known injector properties the fuel table can be pretty accurately calibrated without running the car.
Your actual 100% VE point depends on engine size and cylinder count, and 1 L of air is approx. 1.2g. So for a 4 cycle 2 liter engine actual 100% VE will be in the approximately 60% Eff area (.6g of air per induction).
Re: Efficiency Point of a MAF-based system
Posted:
Wed Nov 30, 2011 4:22 pm
by MarkMc
Inductions per rev.......how many firings for one revolution of the crank. For a 4 cylinder 4 stroke engine it would be 2.
Re: Efficiency Point of a MAF-based system
Posted:
Thu Dec 01, 2011 1:37 pm
by Vassili Wang
MarkMc wrote:Inductions per rev.......how many firings for one revolution of the crank. For a 4 cylinder 4 stroke engine it would be 2.
Thanks a lot!!